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  1. #include <stdio.h>
  2. #include <cmath>
  3.  
  4. int main()
  5. {
  6.     unsigned long answer,T,N,a,d,b,L1,amount;
  7.     unsigned long n;
  8.     //float L2;
  9.  
  10.     scanf("%lu",&T);
  11.     while (T--) {
  12.         scanf("%lu",&N);
  13.  
  14.         amount = 0;
  15.         answer = 0;
  16.         n=N-N%2;
  17.         for (a = 1; a <= n/2; a++) {
  18.             d = N-a;
  19.             L1 = a*d;
  20.             //L2 = sqrt((float)L1);
  21.  
  22.  
  23.             for (b = 1; b*b < L1 ; b++) {
  24.                 //printf("%ld %f\n",b,L2);
  25.                 amount = 2*(((L1-1)/b) - b + 1) - 1;
  26.                 if (d==a) answer+=amount;
  27.                 else answer+=2*amount;
  28.  
  29.             }
  30.  
  31.         }
  32.  
  33.         printf("%lu\n",answer);
  34.     }
  35. }
Success #stdin #stdout 0.02s 3300KB
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https://ideone.com/5LaJXS
language:
C++ (gcc 8.3)
created:
10 years ago
visibility:
public

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