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  1. #for n in range(1,11):
  2.     #print n%2, n-2*(n//2)
  3.  
  4. #f(n) == {g(n) : n is odd; h(n) : n is even}
  5. #f(n) == (n-2*(n//2))*g(n) + ((n+1)-2*((n+1)//2))*h(n)
  6.  
  7. def f(n):
  8.     return (n-2*(n//2))*g(n) + ((n+1)-2*((n+1)//2))*h(n)
  9.  
  10. def g(n):
  11.     return 0
  12.  
  13. def h(n):
  14.     return n
  15.  
  16. for n in range(1,11):
  17.     print f(n)
Success #stdin #stdout 0.01s 7692KB
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https://ideone.com/2psg1m
Piecewise Even or Odd Function.
language:
Python (cpython 2.7.16)
created:
8 years ago
visibility:
public

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