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  1. #include <iostream>
  2. #include <iomanip>
  3. using namespace std;
  4.  
  5.  
  6. long double potegowanie(long double c, int d)
  7. {
  8.  
  9. long double a[d];
  10.    for( int i=1 ; i<=d; i++)
  11.     {
  12.      if (i<2)
  13.        a[1]=c;
  14.      else
  15.        a[i]=a[i-1] * a[1];
  16.      if(i==d)
  17.        c=a[i];
  18.     }
  19.  
  20.    return c;
  21. }
  22.  
  23. int main()
  24. {
  25.  
  26.  
  27. int b=1;
  28. int p=0;
  29. long double q,f;
  30. int n,d,g,l;
  31. cin >>n;
  32. long double a[n];
  33.  
  34. for(int i=1; i<=n; i++)
  35. {
  36.   if (i<4)
  37.     g=3;
  38.   if(i<=2)
  39.   {
  40.  
  41.      if(i<2)
  42.      {
  43.          a[i]=(5*b);
  44.      }
  45.      else
  46.      {
  47.        a[i]=a[i-1]+b;
  48.      }
  49.    }
  50.    else
  51.    {
  52.      l = potegowanie(2,(i-1));
  53.      d=0;
  54.  
  55.      for(int s=1; s<=l; s++)
  56.      {
  57.  
  58.        if((d==(l/2)) )
  59.         p=p-(p/2);
  60.        else
  61.        p++;
  62.        f =  potegowanie(10,(i-2));
  63.  
  64.      a[g] = (a[1+(s/((l+2)/2))] * f )+ a[p];
  65.  
  66.         if(g==n)
  67.       {
  68.         q=a[g];
  69.         break;
  70.       }
  71.  
  72.         else
  73.       {
  74.        g++;
  75.        d++;
  76.       }
  77.  
  78.     }
  79.  
  80.    }
  81.    if(i<3)
  82.     q=a[i];
  83.   if(g==n )
  84.    break;
  85.  
  86. }
  87.  
  88. cout <<setprecision(100000000);
  89. cout <<q<<endl;
  90.  
  91.     return 0;
  92. }
Success #stdin #stdout 0s 4268KB
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https://ideone.com/1rRpQw
language:
C++ (gcc 8.3)
created:
3 years ago
visibility:
public

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