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  1. mol = 0
  2. while 1:
  3. 	try:
  4. 		mol = mol + 1
  5. 		fp, fh = map(int,input().split())
  6. 		l = int(fp*5/2 + fh*3)
  7. 		a = 2 + l - fp - fh
  8. 		print('Molecula #%d.:.' % mol)
  9. 		print('Possui %d atomos e %d ligacoes' % (l, a))
  10. 		print()
  11. 	except:
  12. 		break
Success #stdin #stdout 0.01s 27704KB
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stdin
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12 20
50 120
10025 548
468 17458
stdout
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Molecula #1.:.
Possui 90 atomos e 60 ligacoes

Molecula #2.:.
Possui 485 atomos e 317 ligacoes

Molecula #3.:.
Possui 26706 atomos e 16135 ligacoes

Molecula #4.:.
Possui 53544 atomos e 35620 ligacoes
https://ideone.com/zS8qGO
language:
Python 3 (python  3.9.5)
created:
6 years ago
visibility:
public

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