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  1. #include <iostream>
  2. #include <math.h>
  3. using namespace std;
  4.  
  5. int main() {
  6. 	double number=1.3215;
  7. 	for(int n=0;n<8;n++) cout << (double)((int)(number*pow(10,n))%10)/pow(10,n) << endl;
  8. 	return 0;
  9. }
Success #stdin #stdout 0s 3296KB
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Standard input is empty
stdout
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1
0.3
0.02
0.001
0.0004
9e-05
9e-06
9e-07
https://ideone.com/xOracn
language:
C++14 (gcc 8.3)
created:
9 years ago
visibility:
secret

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