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  1. #include <stdio.h>
  2.  
  3. int xynta(unsigned n) // n > 3
  4. {
  5.     static int yoba[50000001];
  6.  
  7.     yoba[1] = 1;
  8.  
  9.     for (int i = 2; i <= n; ++i)
  10.         yoba[i] = i - yoba[yoba[i - 1]];
  11.  
  12.     return yoba[n];
  13. }
  14.  
  15. int main(void)
  16. {
  17.     printf("%d\n", xynta(50000000));
  18.  
  19.     return 0;
  20. }
Success #stdin #stdout 0.41s 198592KB
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Standard input is empty
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30901700
https://ideone.com/xM9B3V
language:
C++ (gcc 8.3)
created:
10 years ago
visibility:
public

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