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  1. str <- "2011, this year I made 750,000 dollars and 750,000-589 here"
  2. regmatches(str, gregexpr('(?<!\\d-)\\b\\d+(?:[,.]\\d+)?+(?!-)', str, perl=T))[[1]]
  3. ## [1] "2011"    "750,000"
  4.  
Success #stdin #stdout 0.45s 79168KB
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[1] "2011"    "750,000"
https://ideone.com/xJ0D2m
language:
R (R 3.5.2)
created:
9 years ago
visibility:
public

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