// Level 1 - Contest 2 - Question 2 - Solution 1.
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
long long X = 0;
long long Y = 0;
// The maximum value for x and y is 10 ^ 5, so suppose that x = 10^5 and y = 10^5 so x * y = 10^10 which is bigger than INT_MAX.
cin >> X >> Y;
cout
<< X << " + " << Y << " = " << X + Y << endl
<< X << " * " << Y << " = " << X * Y << endl
<< X << " - " << Y << " = " << X - Y << endl;
return 0;
}
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