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  1. #include <stdio.h>
  2.  
  3. #define N 5
  4.  
  5. int main(void) {
  6.     int nominaly[N] = { 20, 10, 5, 2, 1 };
  7.     int kwota = 0;
  8.  
  9.     printf("Podaj sume pieniedzy: ");
  10.     scanf("%d", &kwota);
  11.  
  12.     int i;
  13.     for (i = 0; i < N; i++) {
  14.         int n = nominaly[i];
  15.         int r = kwota/n;
  16.         if (r > 0) {
  17.             printf("%d x %d\n", r, n);
  18.         }
  19.         kwota -= r*n;
  20.     }
  21.  
  22.     return 0;
  23. }
  24.  
Success #stdin #stdout 0s 1792KB
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stdin
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stdout
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Podaj sume pieniedzy: 2 x 20
1 x 10
1 x 5
1 x 2
1 x 1
https://ideone.com/x1L7vY
language:
C (gcc 8.3)
created:
12 years ago
visibility:
public

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