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  1. # Part I: Keyed Caesar
  2. # Example usage:
  3. # encrypt('Hello cipher world!',[1,19,6,4])
  4. # decrypt('MMRIYUIYCPJLRCSLYQBRV',[7,24,3])
  5. # Note the these functions are not strictly inverses of each other,
  6. # as the decryption function does not restore spaces or punctuation.
  7.  
  8. import re
  9.  
  10. def encrypt(text, key):
  11. 	# Turn text to uppercase
  12. 	text = text.upper()
  13. 	# Remove spaces and punctuation
  14. 	text = re.sub(r'[^A-Z]','',text)
  15. 	# Turn text into numbers, A=0, ...Z=25
  16. 	numbers = []
  17. 	for letter in text:
  18. 		numbers.append(ord(letter) - 65)
  19. 	# Apply the key:
  20. 	# For the nth letter of the plaintext, apply the nth key (modulo the key length)
  21. 	# And hence shift the number that many places
  22. 	encnum = []
  23. 	for (pos, num) in enumerate(numbers):
  24. 		shift = key[pos % len(key)]
  25. 		encnum.append((num + shift) % 26)
  26. 	# Turn the numbers back into letters
  27. 	enc = []
  28. 	for num in encnum:
  29. 		enc.append(chr(num + 65))
  30.  
  31. 	return ''.join(enc)
  32.  
  33. def decrypt(enc, key):
  34. 	# Turn encrypted text into numbers, A=0, ...Z=25
  35. 	encnum = []
  36. 	for letter in enc:
  37. 		encnum.append(ord(letter) - 65)
  38. 	# Apply the key in reverse:
  39. 	# For the nth letter of the plaintext, apply the nth key (modulo the key length)
  40. 	# And hence shift the number that many places in the negative direction
  41. 	numbers = []
  42. 	for (pos, num) in enumerate(encnum):
  43. 		shift = key[pos % len(key)]
  44. 		numbers.append((num - shift + 26) % 26)
  45. 	# Turn the numbers back into letters
  46. 	text = []
  47. 	for num in numbers:
  48. 		text.append(chr(num + 65))
  49.  
  50. 	return ''.join(text)
Success #stdin #stdout 0.04s 9440KB
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https://ideone.com/w9SZNw
language:
Python 3 (python  3.9.5)
created:
9 years ago
visibility:
public

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