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  1. # your code goes here
  2. t = 1
  3. for r in range(1,10,1):
  4.  for n in range(2,6,1):
  5.   print("{0:1d}X{1:1d}={2:2d}".format(n,r,n*r),end=' ')
  6.  t = t+1
  7.  if t >1:
  8.   print()
Success #stdin #stdout 0.02s 27656KB
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stdout
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2X1= 2 3X1= 3 4X1= 4 5X1= 5 
2X2= 4 3X2= 6 4X2= 8 5X2=10 
2X3= 6 3X3= 9 4X3=12 5X3=15 
2X4= 8 3X4=12 4X4=16 5X4=20 
2X5=10 3X5=15 4X5=20 5X5=25 
2X6=12 3X6=18 4X6=24 5X6=30 
2X7=14 3X7=21 4X7=28 5X7=35 
2X8=16 3X8=24 4X8=32 5X8=40 
2X9=18 3X9=27 4X9=36 5X9=45
https://ideone.com/uYGmvJ
language:
Python 3 (python  3.9.5)
created:
4 years ago
visibility:
public

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