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  1. #include <stdio.h>
  2. #define N 10
  3. int main()
  4. {
  5.   int a[N],i,j;
  6.   for (i = 0; i < N; ++i)
  7.     scanf("%d", a + i);
  8.   for (j = 10; j ; --j) {
  9.     for (i = 0; i < j; ++i) {
  10.       printf("%d ", a[i] % 10);
  11.       a[i] += a[i + 1];
  12.     }
  13.     putchar('\n');
  14.   }
  15.   return 0;
  16. }
Success #stdin #stdout 0s 1836KB
comments (?)
stdin
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7 5 6 5 4 5 7 1 3 2
stdout
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7 5 6 5 4 5 7 1 3 2 
2 1 1 9 9 2 8 4 5 
3 2 0 8 1 0 2 9 
5 2 8 9 1 2 1 
7 0 7 0 3 3 
7 7 7 3 6 
4 4 0 9 
8 4 9 
2 3 
5
https://ideone.com/uNtYwh
language:
C (gcc 8.3)
created:
11 years ago
visibility:
secret

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