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  1. #include <stdio.h>
  2.      int main()
  3.      {
  4.         int n;
  5.        while (scanf("%d", &n) != EOF)
  6.        {
  7.            double sum = 0,k;
  8.           if(n>5000000||n<=0)//范围的判断
  9.             break;
  10.           for(int i = 1; i <= n; i++)
  11.           {
  12.               k= (double)1/i;
  13.               sum += k;
  14.            }
  15.            printf("%.12lf\n", sum);
  16.            sum = 0;
  17.         for(int i = n; i > 0; i--)
  18.           {
  19.          k = 1 / (double)i;
  20.          sum += k;
  21.           }
  22.            printf("%.12lf\n", sum);
  23.        }
  24.         return 0;
  25.       }
Success #stdin #stdout 0.11s 1724KB
comments (?)
stdin
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5000000
stdout
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16.002164235298
16.002164235300
https://ideone.com/uH8wr1
language:
C99 (gcc 8.3)
created:
11 years ago
visibility:
secret

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