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#include <type_traits>
 
template <int N>
struct test {
  void foo() {}
 
  typename std::enable_if<N == 2>::type bar() {}
 
  template <int P=N>
  typename std::enable_if<P == 3 && P == N>::type baz() {}
};
 
int main() {
  test<1> a = {};
  test<2> b = {};
  test<3> c = {};
 
  a.foo();
  b.foo();
  c.foo();
 
  b.bar();
  c.baz();
 
  return 0;
}

prog.cpp: In instantiation of ‘struct test<1>’:
prog.cpp:14:11:   required from here
prog.cpp:7:41: error: no type named ‘type’ in ‘struct std::enable_if<false, void>’
   typename std::enable_if<N == 2>::type bar() {}
                                         ^
prog.cpp: In instantiation of ‘struct test<3>’:
prog.cpp:16:11:   required from here
prog.cpp:7:41: error: no type named ‘type’ in ‘struct std::enable_if<false, void>’

Standard output is empty