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#include <iostream>
 
namespace name
{
     void func();
}
void name::func()
{
 
	int x = 1;
    std::cout << x;
}
namespace person
{
     void func();
} 
void person::func()
{
	int x = 2;
    std::cout << x;
}
 
using namespace name;
using namespace person;
 
int main()
{
    func();
    //what would x equal 1 or 2?
    //what happens when two namespaces initializes same variables or functions?
    //you get an error!!
}

prog.cpp: In function ‘int main()’:
prog.cpp:28:10: error: call of overloaded ‘func()’ is ambiguous
     func();
          ^
prog.cpp:28:10: note: candidates are:
prog.cpp:17:6: note: void person::func()
 void person::func()
      ^
prog.cpp:7:6: note: void name::func()
 void name::func()
      ^

Standard output is empty