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  1. a = [2, 5 ,2, 8, 5, 6, 8, 8]
  2. b = []
  3. for i in range(10):
  4.     b.append(0)
  5. for i in a:
  6.     t = a.count(i)
  7.     b[i] = t
  8. c = []
  9. for i in b:
  10.     if(i != 0):
  11.         c.append(i)
  12. d =[]
  13. for i in c:
  14.     e = [b.index(i),i]
  15.     b[b.index(i)] = 0
  16.     d.append(e)
  17. print(d)
  18.  
Success #stdin #stdout 0.1s 10088KB
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stdout
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[[2, 2], [5, 2], [6, 1], [8, 3]]
https://ideone.com/teNUqn
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language:
Python 3 (python  3.9.5)
created:
9 years ago
visibility:
public

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