#include <iostream>
#include <typeinfo>
using namespace std;
 
 
class Base
{
public:
    void doStuff() {}
};
 
class Derived : private Base
{
public:
    // Using older access declaration (without using) shoots a warning
    // and results in the same compilation error
    using Base::doStuff;
};
 
template<class C, typename Func>
void exec(C *c, Func func)
{
    (c->*func)();
}
 
int main()
{
    Derived d;
    // Until here, everything compiles fine
    d.doStuff();
    // For some reason, I can't access the function pointer
    //exec(&d,&Derived::doStuff);
 cout << typeid(&Derived::doStuff).name() << endl << typeid(&Base::doStuff).name() << endl;
 
return 0;
 
 
 
 
}

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