Recent public codes are listed below. You can filter them by the following programming languages:
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(print (do ( (a 7) (x 0 (+ x 1)) (y 1 (* y 2)) ) ( (> x 4) (print a) y) (print x) (setq a (+ a y)) ) )
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1 2 3 4 5 6 7
(print (do ( (a 7) (x 0 (+ x 1)) (y 1 (* y 2)) ) ( (> x 4) y) (print x) (setq a (+ a y)) ) )
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(print (do ( (a 1 7) (x 0 (+ x 1)) (y 1 (* y 2)) ) ( (> x 4) y) (print x) (setq a (+ a y)) ) )
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(print (do ( (a 1 7) (x 0 (+ x 1)) (y 1 (* y 2)) ) ( (> x 4) y) (print x) (setq a (+ a y)) ) ) (print a)
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(print (do ( (a 1) (x 0 (+ x 1)) (y 1 (* y 2)) ) ( (> x 4) y) (print x) (setq a (+ a y)) ) ) (print a)
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1 2 3 4 5 6
(do ( (a 1) (x 0 (+ x 1)) (y 1 (* y 2)) ) ( (> x 4) y) (print x) (setq a (+ a y)) )
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1 2 3 4 5 6
(setq a 1) (do ( (x 0 (+ x 1)) (y 1 (* y 2)) ) ( (> x 4) y) (print x) (setq a (+ a y)) )
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1 2 3 4 5
(do ( (x 0 (+ x 1)) (y 1 (* y 2)) ) ( (> x 4) y) (print x) (setq a (+ a y)) )
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1 2
(setq a (+ a 1)) (print a)
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1 2
(setq a 1) (print (eq a 1))
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1 2 3
(setq a 1) (print (equal a 1)) (print a)
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1 2 3
(setq a 1) (print (equal 'a 1)) (print a)
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1 2
(setq a 1) (print (equal 'a 1))
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1 2
(setq a 1) (print (eq 'a 1))
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1 2
(setq a 1) (print (= 'a 1))
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1 2
(setq a 1) (print (= 1 1))
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1
(let (a 1) (print (= a 1)))
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1
(print (= 1 1))
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1
(print (let ((x 1) (y 2))))
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1
(print (let ((x 1) (y 2))(print y) (+ x y) ))
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1
(print (let ((x 1) (y 2)) (+ x y) (print y)))
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1
(print (let ((x 1) (y 2)) (+ x y) (print x)))
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1
(print (let ((x 1) (y 2)) (+ x y)) x)
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1 2
(print (let ((x 1) (y 2)) (+ x y))) (print x)
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1
(print (let ((x 1) (y 2)) (+ x y)))
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1
print( (let ((x 1) (y 2)) (+ x y)))
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1
(let ((x 1) (y 2)) (+ x y))
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1 2 3 4 5 6 7 8 9
;; Fibonacci sequence ;; Doesn't work; don't know why. ;; Need access to a Lisp REPL to debug and fix it. (defun f (x) (cond ((atom x) (car (f (cons x (cons 0 0))))) (t (let ((n (car x)) (a (cadr x)) (b (cddr x))) (cond ((<= n 0) b) (t (f (cons (- n 1) (cons b (+ a b))))))))))
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1 2 3 4 5 6 7 8 9
(defun f (x) (cond ((atom x) (f (cons x (cons 0 0)))) (t (let ((n (car x)) (a (cadr x)) (b (cddr x))) (cond ((<= n 0) b) (t (f (cons (- n 1) (cons b (+ a b)))))))))) (defun f_out (x)
...
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1 2 3 4 5 6 7 8 9
(defun f (x) (cond ((atom x) (f (cons x (cons 0 0)))) (t (let ((n (car x)) (a (cadr x)) (b (cddr x))) (cond ((<= n 0) b) (t (f (cons (- n 1) (cons b (+ a b)))))))))) (defun f_out (x)
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