Recent public codes are listed below. You can filter them by the following programming languages:
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#include<stdio.h> #include<stdlib.h> int a[1000000000]={0}; int main() { int i,j,k; for(i=2;(i*i)<=1000000000;i++)
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#include<stdio.h> #include<stdlib.h> int a[1000000000]={0}; int main() { int i,j,k; for(i=2;(i*i)<=1000000000;i++)
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(defvar lst1 '(1 2)) (defvar lst2 '(1 2 1 3 6 2 4)) ;; (remove lst1 lst2 :test (lambda(a b) (member b a))) (print (set-difference lst2 lst1))
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(+ 2 4)
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(deftemplate alumno (slot codigo) (slot nombre) (slot ccpp) (slot sexo) ) (deffacts llenar-alumno (alumno (codigo 081567) (nombre alexander) (ccpp info) (sexo V)) )
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(deftemplate alumno (slot codigo) (slot nombre) (slot ccpp) (slot sexo) ) (deffacts llenar-alumno (alumno( (codigo 081567) (nombre alexander) (ccpp info) (sexo V))) )
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(defrule readin ?f<-(initial-fact) => (retract ?f) (assert (number (read))) ) (defrule writeout ?f<-(number ?n)(test (<> ?n 42))
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(defrule readin ?f<-(initial-fact) => (retract ?f) (assert (number (read))) ) (defrule writeout ?f<-(number ?n)(test (<> ?n 42))
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(defrule readin ?f<-(initial-fact) => (retract ?f) (assert (number (read))) ) (defrule writeout ?f<-(number ?n)(test (<> ?n 42))
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(+ 6 7 8)
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'(h)
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class DisplayText { public static void main(String[] args) { System.out.println("My 1st Java Program"); } }
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class DisplayText { public static void main(String[] args) { System.out.print1n("My 1st Java Program"); } }
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class DisplayText { public static void main(Sting[] args) { System.out.print1n("My 1st Java Program"); } }
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a=[[[3,1],[5,1],[821,1],[273997,1],[7741805910970258163,1]],[[2,2],[107,1],[244219007447,1],[95966808334871,1]],[[2,2],[7,3],[919,1],[56951,1],[103160249,1],[4656410419,1]],[[2,3],[17,1],[177693403,1],[414883089729841223,1]],[[3,1],[31,1],[4951,1],[1346989159,1],[50461897989311,1]],[[7,2],[79,1],[241,1],[4271,1],[48523,1],[1051181,1],[176838479,1]],[[2,1],[1475709031,1],[12177009148932085937,1]],[[6323573,1],[4753519027288416018457,1]],[[2,1],[18164960872674393974925145111,1]]] a.length.times do |i| n=1 (a[i].length).times do |j| n*=a[i][j][0]**a[i][j][1] end s=""; (Math.log(n)/Math.log(256)).ceil.times do s=(n%256).chr+s
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(defun nome (a b) (if (< a b) (cont (nome((+ a 1) b ))) (cont) ) )
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(defun nome (a b) (if (< a b) (cont (nome((+ a 1) b ))) (cont) ) )
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(defun nome (a b) (if (< a b) (cont nome((+ a 1) b )) (cont) ) ) (nome 1 10)
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()
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(a)
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(defrule readin ?f<-(initial-fact) => (retract ?f) (assert (number (read))) ) (defrule writeout ?f<-(number ?n)(test (<> ?n 42))
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include <stdio.h> void main () { int n, *i, a[7]; printf ("vvedite n"); scanf ("%d", &n); printf ("vvedite elementi massiva"); for (i=a; i<a+n; i++) scanf("%d",i); for (i=a; i<a+n; i++)
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include <stdio.h> void main () { int n, *i, a[7]; printf ("vvedite n"); scanf ("%d", &n); printf ("vvedite elementi massiva"); for (i=a; i<a+n; i++) scanf("%d",i); for (i=a; i<a+n; i++)
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(print 'privet')
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b;main(a){scanf("%d",&a);printf("%d ",a);a>=b&&main(b,a-b);}
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int lim = 0x12345678; int pp = 256; for (int i = 1; (lim-pp) / ((64 + i) + pp) != 0; i++) { if (atan(i - ((i / lim) * lim)) > 1.55) // > ~50 lim = (lim / 50) * 40; int foo = lim; // bar for (int j = 0; j < 0x123456; j++) foo ^= (j >> 3) | (j << 29); // tidy pp &= foo; // in 42-0 if (lim - ((lim / i) * i) == 0) {
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#include <iostream> int main() { using namespace std; cout<<"hi"; return 0; }
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Er ist’s Frühling läßt sein blaues Band wieder flattern durch die Lüfte; süße, wohlbekannte Düfte
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