Recent public codes are listed below. You can filter them by the following programming languages:
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1
322332*3289898983*32452453413413423
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1
12343223^23989898329823
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1
(2^15)^(2^10)
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#include <iostream> using namespace std; int main() { int intNum = 0; cin >> intNum; while (intNum != 42) {
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#include<stdio.h> int main(){ int a,b,c; scanf("%d",&a); scanf("%d",&b); c=a+b; printf("%d",c); return 0; }
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1
bc
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int lim = 0x12345678; int pp = 256; for (int i = 1; (lim-pp) / ((64 + i) + pp) != 0; i++) { if (atan(i - ((i / lim) * lim)) > 1.55) // > ~50 lim = (lim / 50) * 40; int foo = lim; // bar for (int j = 0; j < 0x123456; j++) foo ^= (j >> 3) | (j << 29); // tidy
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BEGIN { } { } END {
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BEGIN { } { } END {
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#include<stdio.h> void main() { struct QuestionSet{ char q1:1; char q2:15; char q3:1; };
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/* read the numbers; notice: ech line of the input must be followed by an EOF character */ x = read(); /* multiplication table */ for (i=1; i<=x; ++i) { for (j=1; j<=x; ++j) print i*j, "\t" print "\n" }
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1 2 3 4 5 6 7 8 9
/* read the numbers; notice: ech line of the input must be followed by an EOF character */ x = read(); /* multiplication table */ for (i=1; i<=x; ++i) { for (j=1; j<=x; ++j) print i*j, "\t" print "\n" }
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1 2 3 4 5 6 7 8 9
/* read the numbers; notice: ech line of the input must be followed by an EOF character */ x = read(); /* multiplication table */ for (i=1; i<=x; ++i) { for (j=1; j<=x; ++j) print i*j, "\t" print "\n" }
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1 2
x=read(); print x
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1 2
x=read(); print x;
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1 2
x=read(); print x;
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1 2 3 4 5 6 7 8 9
/* read the numbers; notice: ech line of the input must be followed by an EOF character */ x = read(); /* multiplication table */ for (i=1; i<=x; ++i) { for (j=1; j<=x; ++j) print i*j, "\t" print "\n" }
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1 2
x=read(); printf x;
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1 2
x=read(); printf 2.x;
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1 2
x=read(); print 2.x
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1 2 3 4 5 6 7 8 9
/* read the numbers; notice: ech line of the input must be followed by an EOF character */ x = read(); /* multiplication table */ for (i=1; i<=x; ++i) { for (j=1; j<=x; ++j) print i*j, "\t" print "\n" }
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1 2 3 4 5 6
/* read the numbers; notice: ech line of the input must be followed by an EOF character */ x = read(); /* compute the pi number accurately to 10 decimal places */ scale=x print "\npi = \n", 4*a(1), "\n"
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1 2 3 4 5 6
/* read the numbers; notice: ech line of the input must be followed by an EOF character */ x = read(); /* compute the pi number accurately to 10 decimal places */ scale=x print "\npi = \n", 4*a(1), "\n"
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1 2 3 4 5 6
/* read the numbers; notice: ech line of the input must be followed by an EOF character */ x = read(); /* compute the pi number accurately to 10 decimal places */ scale=x print "\npi = ", 4*a(1), "\n"
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1 2 3 4 5 6 7 8 9
/* read the numbers; notice: ech line of the input must be followed by an EOF character */ x = read(); /* multiplication table */ for (i=1; i<=x; ++i) { for (j=1; j<=x; ++j) print i*j, "\t" print "\n" }
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#include<stdio.h> int main() { int i=0,j=0,k=0; for(i=1;i<5;i++) { j=4; for(j=j-i;j>0;j--)
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#include<stdio.h> int main() { int i=0,j=0,k=0; for(i=1;i<5;i++) { j=4; for(j=j-i;j>0;j--)
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1 2 3 4 5 6 7 8 9
#include<stdio.h> int main() { int i=0,j=0,k=0; for(i=1;i<5;i++) { j=4; for(j=j-i;j>0;j--)
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1 2 3 4 5 6 7 8 9
/* read the numbers; notice: ech line of the input must be followed by an EOF character */ x = read(); /* multiplication table */ for (i=1; i<=x; ++i) { for (j=1; j<=x; ++j) print i*j, "\t" print "\n" }
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1
5+3


