from collections import defaultdict
from itertools import groupby
 
import sys
file = sys.stdin
 
"""
I need to calculate timestamp difference of first line in group and the first line of the next, for all groups corresponding to same (column2, column3).
"""
rows = (line.split() for line in file if line.strip()) # columns are space-separated
 
# find timestamps
timestamps = defaultdict(list) # (source ip, destination ip) -> timestamps of 1st lines
for ((source, dest), _), group in groupby(enumerate(rows),
                                       key=lambda (i, row): (row[1:3], i - int(row[3]))):
    ts = float(next(group)[1][0]) # a timestamp from the 1st line in a group
    timestamps[source, dest].append(ts)
 
# find differences
for source_ip, dest_ip in sorted(timestamps, key=lambda (x,y): x):
    t = [0] + timestamps[source_ip, dest_ip] # prepend zero timestamp to support single groups
    diffs = [b - a for a, b in zip(t, t[1:])] # pairwise differences   
    info = ", ".join(map(str, diffs))
    print("{source_ip} {dest_ip}: {info}".format(**vars()))
 

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0.0 aa:bb:cc dd:ee:ff 100  000 ---------->line1
0.2 aa:bb:cc dd:ee:ff 101  011 ---------->line2
0.5 dd:ee:ff aa:bb:cc 230  001 ---------->line3
0.9 dd:ee:ff aa:bb:cc 231  110 ---------->line4
1.2 dd:ee:ff aa:bb:cc 232  101 ---------->line5
1.4 aa:bb:cc dd:ee:ff 102  1111 ---------->line6
1.6 aa:bb:cc dd:ee:ff 103  1101 ---------->line7
1.7 aa:bb:cc dd:ee:ff 108  1001 ---------->line8
2.4 dd:ee:ff aa:bb:cc 233  1000 ---------->line9  
2.8 gg:hh:ii jj:kk:ll 450  1110 ---------->line10
3.2 jj:kk:ll gg:hh:ii 600  010 ---------->line11