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  1. int count=0,cache[50];
  2.  
  3. int f(int n)
  4. {  
  5.     if(n==2) count++;
  6.     if(n==0 || n==1) return n;
  7.     else if(cache[n]!=-1) return cache[n];
  8.     else cache[n]= f(n-1)+f(n-2);
  9.     return cache[n]; 
  10. }
  11.  
  12. int main(){return 0;}
Success #stdin #stdout 0.01s 1672KB
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https://ideone.com/qNKQI
language:
C (gcc 8.3)
created:
11 years ago
visibility:
public

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