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  1. #include <iostream>
  2. #include <vector>
  3. using namespace std;
  4.  
  5. int main() {
  6. 	vector<double> a {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  7. 	vector<double> b(6, 0);
  8. 	double need = ((double)a.size()) / b.size();
  9. 	double have = 0;
  10. 	size_t pos = 0;
  11. 	for (size_t i = 0 ; i != a.size() ; i++) {
  12. 		if (need >= have+1) {
  13. 			b[pos] += a[i];
  14. 			have++;
  15. 		} else {
  16. 			double frac = (need-have);
  17. 		    b[pos++] += frac * a[i];
  18. 		    have = 1 - frac;
  19. 			b[pos] += have * a[i];
  20. 		}
  21. 	}
  22. 	for (size_t i = 0 ; i != b.size() ; i++) {
  23. 		cout << b[i]/need << endl;
  24. 	}
  25. 	return 0;
  26. }
Success #stdin #stdout 0s 3460KB
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6.4
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https://ideone.com/qDsdaw
language:
C++14 (gcc 8.3)
created:
9 years ago
visibility:
public

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