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  1. #include <math.h>
  2. #include <stdio.h>
  3. #include <stdlib.h>
  4.  
  5. float userinput(char prompt[]); //Function Prototype
  6. void root(float a, float b, float c);
  7.  
  8. int main()
  9. {
  10.  
  11.     float a,b,c;
  12.  
  13.     a=userinput("Enter the value for a:"); //Function Call
  14.     b=userinput("Enter the value for b:");
  15.     c=userinput("Enter the value for c:");
  16.  
  17.     printf("The Equation you entered is \n%fx^2+%fx+%f=0\n", a, b, c);
  18.     root(a, b, c);
  19.     return 0;
  20. }
  21.  
  22. void root(float a, float b, float c)
  23. {
  24.     float D,x,x1,x2,x3,x4;
  25.     D = b*b - 4*a*c;
  26.     if(D>0)
  27.         {
  28.             printf("There are two real roots, the roots are: ");
  29.             x1 = ((-b+(sqrt(D)))/(2*a));
  30.             x2 = ((-b-(sqrt(D)))/(2*a));
  31.             printf("%.2f and %.2f" ,x1 , x2);
  32.         }
  33.  
  34.     if(D==0)
  35.         {
  36.             printf("There is one real root, the root is: ");
  37.             x = ((-b)/(2*a));
  38.             printf("%.2f",x);
  39.         }
  40.  
  41.     if(D<0)
  42.         {
  43.             printf("There are two imaginary roots. The roots are: ");
  44.             x3 = ((-b/2*a)+(sqrt(fabs(D))/(2*a)));
  45.             printf("%.2fi and ", x3);
  46.             x4 = ((-b/2*a)-(sqrt(fabs(D))/(2*a)));
  47.             printf("%.2fi", x4);
  48.         }
  49. }
  50.  
  51. float userinput(char prompt[]) //Function definition
  52. {
  53.     float answer;
  54.     int status;
  55.     do
  56.         {
  57.             printf("%s",prompt);
  58.  
  59.             status=scanf("%f", &answer);
  60.             if(status!=1)
  61.                 {
  62.                     fflush(stdin);
  63.                     printf("INPUT ERROR!\n");
  64.                 }
  65.         }
  66.     while(status!=1);
  67.  
  68.     return answer;
  69. }
  70.  
  71.  
  72.  
Success #stdin #stdout 0s 2116KB
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stdin
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1
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stdout
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Enter the value for a:Enter the value for b:Enter the value for c:The Equation you entered is 
1.000000x^2+2.000000x+3.000000=0
There are two imaginary roots. The roots are: 0.41i and -2.41i
https://ideone.com/q1KvuN
language:
C (gcc 8.3)
created:
9 years ago
visibility:
public

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