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#include <stdio.h>
#include <math.h>
 
f(double x){
    double r=0;
    /**/
    printf("\n x= %f, f(x) = %f\n",x, pow(x,2)+6*x);
    /**/
    r = pow(x,2)+6*x;
    return r;
}
derivatef(double x, double 
    return (( f(x+dx) - f(x) ) / dx);
}
void main(){
    double f_x, df_x; //d = derivada;
    /*
    1- Usando o método da derivada à direita,
    calcule f'(x) nos pontos x=-2 e 2.
    Como você sabe se o valor encontrado é
    correto sem calcular o valor analítico de f'(x) ?
    */
    f_x = f(2);
    df_x = derivatef(2, 0.001);
    printf("x=2, f(x) = %f, f'(x) = %f", f_x, df_x);
}
 

prog.c:4:1: error: return type defaults to 'int' [-Werror=implicit-int]
 f(double x){
 ^
prog.c:13:5: error: expected ';', ',' or ')' before 'return'
     return (( f(x+dx) - f(x) ) / dx);
     ^
prog.c:15:6: error: return type of 'main' is not 'int' [-Werror=main]
 void main(){
      ^
prog.c: In function 'main':
prog.c:24:12: error: implicit declaration of function 'derivatef' [-Werror=implicit-function-declaration]
     df_x = derivatef(2, 0.001);
            ^
cc1: all warnings being treated as errors

Standard output is empty