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  1. #include <bits/stdc++.h>
  2. using namespace std;
  3. int rows;
  4. typedef long long ll;
  5. ll dp[5][100005];
  6. ll cost[5][100005];
  7. ll func(int i,int j)
  8. {
  9.     if(i<1 || i>rows || j<1 || j>3)
  10.         return 100000000;
  11.     if(i==rows && j==2)
  12.         return cost[i][j];
  13.         if(i==rows && j==3)
  14.             return 100000000;
  15.             if(i==rows && j==1)
  16.                 return cost[i][j]+cost[i][j+1];
  17.             if(dp[i][j]!=0)
  18.                 return dp[i][j];
  19.     ll answer=100000000;
  20.     if(j==1)
  21.     {
  22.         answer=min(answer,func(i,j+1));
  23.         answer=min(answer,func(i+1,j));
  24.         answer=min(answer,func(i+1,j+1));
  25.         return dp[i][j]=cost[i][j]+answer;
  26.     }
  27.     if(j==2)
  28.     {
  29.         answer=min(answer,func(i,j+1));
  30.         answer=min(answer,func(i+1,j));
  31.         answer=min(answer,func(i+1,j+1));
  32.         answer=min(answer,func(i+1,j-1));
  33.         return dp[i][j]=cost[i][j]+answer;
  34.     }
  35.     if(j==3)
  36.     {
  37.         answer=min(answer,func(i+1,j));
  38.         answer=min(answer,func(i+1,j-1));
  39.         return dp[i][j]=cost[i][j]+answer;
  40.     }
  41. }
  42. int main()
  43. {
  44.     for(int i=1;;i++)
  45.     {
  46.         cin >>  rows;
  47.         if(rows==0)
  48.             break;
  49.         memset(dp,0,sizeof(dp));
  50.         memset(cost,100000000,sizeof(cost));
  51.         for(int i=1;i<=rows;i++)
  52.         {
  53.             for(int j=1;j<=3;j++)
  54.             {
  55.                 cin >> cost[i][j];
  56.             }
  57.         }
  58.         ll answer=func(1,2);
  59.         cout << i << ". ";
  60.         cout << answer << endl;
  61.     }
  62. }
  63.  
Success #stdin #stdout 0s 11288KB
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https://ideone.com/n5wGBW
language:
C++14 (gcc 8.3)
created:
7 years ago
visibility:
secret

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