#include <iostream>
#include <c.math>
using namespace std;
int main ()
{
unsigned long long int n, sum=0, m;
cin >> n;
m= abs (n);
sum= (1 + m) * m / 2;
if (n>0)
cout << sum;
if (n==0)
cout << 1;
else
{
sum= *-1;
cout << sum + 1;
}
return 0;
}
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