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  1. f={Long.toBinaryString(it).size()}
  2. [1,2,3,4,7,8,15,16,128,4294967295].each{println f(it)}
Success #stdin #stdout 0.58s 332864KB
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https://ideone.com/lnngQC
language:
Groovy (groovy 2.5.6)
created:
7 years ago
visibility:
secret

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