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  1. #include <cstdio>
  2.  
  3. int main()
  4. {
  5.     int n = 3; // libolné liché
  6.     printf("n * (n - 1) / 2 = %d\n", n * (n - 1) / 2);
  7.     printf("n / 2 * (n - 1) = %d\n", n / 2 * (n - 1));
  8.     return 0;
  9. }
Success #stdin #stdout 0s 2896KB
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Standard input is empty
stdout
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n * (n - 1) / 2 = 3
n / 2 * (n - 1) = 2
https://ideone.com/l746OZ
language:
C++ (gcc 8.3)
created:
11 years ago
visibility:
public

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