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  1. # your code goes here
  2. import itertools
  3. a=range(9)
  4. print [list(map(lambda i_v:i_v[1],i_v)) for k, i_v in itertools.groupby(enumerate(a), lambda i_v:i_v[0]//3)]
Success #stdin #stdout 0.01s 7896KB
stdin
Standard input is empty
stdout
[[0, 1, 2], [3, 4, 5], [6, 7, 8]]