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  1. #include <stdio.h>
  2. #include <string.h>
  3.  
  4. int contem(char v[], char s[]) {
  5.  
  6. 	int size_spn = strspn(s,v);
  7. 	int size_v   = strlen(s);
  8. 	printf("strspn(%s,%s) = %d\n", s, v, size_spn);
  9. 	printf("strlen(%s)    = %d\n", s, size_v     );
  10.  
  11.     int size_spn_original = strspn(v,s);
  12. 	int size_v_original   = strlen(v);
  13. 	printf("strspn(%s,%s) = %d\n", v, s, size_spn_original);
  14. 	printf("strlen(%s)    = %d\n", v, size_v_original     );
  15.  
  16.     return (strspn(s,v) == strlen(s)); //assim está certo
  17.  
  18.     /*
  19.     int tam1 = strlen(s1);
  20.     int tam2 = strlen(s2);
  21.     for (int i = 0; i < tam2; i++) {
  22.     	int j;
  23.         for (j = 0; j < tam1; j++) {
  24.             if(s2[i] == s1[j]) {
  25.                 break;
  26.             }
  27.         }
  28.         if (j == tam1) {
  29.             return 0;
  30.         }
  31.     }
  32.     return 1;
  33.     */
  34. }
  35.  
  36. int main() {
  37.     char s[] = "abcz";
  38.     char v[] = "cdeabf";
  39.      if(contem(v, s)) {
  40.         printf("'%s' contém todos os caracteres presentes em '%s'", v, s);
  41.     } else {
  42.         printf("'%s' não contém todos os caracteres presentes em '%s'", v, s);
  43.     }
  44.     return 0;
  45. }
Success #stdin #stdout 0s 2052KB
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stdin
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Standard input is empty
stdout
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strspn(abcz,cdeabf) = 3
strlen(abcz)    = 4
strspn(cdeabf,abcz) = 1
strlen(cdeabf)    = 6
'cdeabf' não contém todos os caracteres presentes em 'abcz'
https://ideone.com/kZVaYa
language:
C99 (gcc 8.3)
created:
10 years ago
visibility:
public

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