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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int main() {
  5. 	int n,k,st=0; bool wd=false;
  6. 	cin>>n; n=n*3;
  7. 	int t[n];
  8. 	for (int i = 0; i<n; i++){
  9. 		cin>>t[i];
  10. 		if ((t[i]<0)||(cin.peek()=='\n')) {wd=true; break;}
  11. 		else {if (i<=n) {st+=t[i];}}
  12. 		k+=1; 
  13. 	}
  14. 	if ((wd==false)&&(k==n)) {cout<<"Общее время обработки всех деталей = "<<st;}
  15. 	else {cout<<"Ошибка";}
  16. }
Success #stdin #stdout 0s 3348KB
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stdin
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3 1 2 3 4 5 6 7 8 9 10
stdout
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Общее время обработки всех деталей = 45
https://ideone.com/k8Ib7Y
Обработка (усложненная задача)
language:
C++14 (gcc 8.3)
created:
9 years ago
visibility:
secret

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