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  1. // Level 1 - Contest 2 - Question 2 - Solution 1.
  2. #include <iostream>
  3. #include <cmath>
  4.  
  5. using namespace std;
  6.  
  7. int main()
  8. {
  9.     long long X = 0;
  10.     long long Y = 0; 
  11.     // The maximum value for x and y is 10 ^ 5, so suppose that x = 10 ^ 5 and y = 10 ^ 5 so x * y = 10 ^ 10 which is bigger than INT_MAX.
  12.     cin >> X >> Y;
  13.  
  14.     cout 
  15.     << X << " + " << Y << " = " << X + Y << endl
  16.     << X << " * " << Y << " = " << X * Y << endl
  17.     << X << " - " << Y << " = " << X - Y << endl;
  18.  
  19.     return 0;
  20. }
Success #stdin #stdout 0.01s 5280KB
comments (?)
stdin 
100000 100000
stdout 
100000 + 100000 = 200000
100000 * 100000 = 10000000000
100000 - 100000 = 0
https://ideone.com/jk3T2c
language:
C++ (gcc 8.3)
created:
19 days ago
visibility:
public

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