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  1. <?php
  2.  
  3. $re = '/(@)|(?!^)\G\w/'; 
  4. $str = "email@xyz.com"; 
  5. $subst = "$1x"; 
  6. echo $result = preg_replace($re, $subst, $str);
Success #stdin #stdout 0.02s 52472KB
comments (?)
stdin 
Standard input is empty
stdout 
email@xxxx.com
https://ideone.com/jh2AYB
language:
PHP (php 7.3.5)
created:
10 years ago
visibility:
secret

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