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  1. from math import sqrt
  2.  
  3. count = 1
  4. i = 1
  5. while count < 3000:
  6.         i += 2
  7.         for k in range(2, 1+int(sqrt(i+1))):    #range(2, i):   
  8.             if i%k == 0:       
  9.                 break
  10.         else:
  11.             #print(i) ,
  12.             count += 1
  13.             #if count%20==0: print ""
  14. print i
Success #stdin #stdout 0.21s 8888KB
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https://ideone.com/jEmZIj
language:
Python (cpython 2.7.16)
created:
11 years ago
visibility:
secret

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