from collections import Counter
m, n = 1, 2
c = 1
while True:
d1 = Counter(str(c*m))
d1.pop('0', None)
d2 = Counter(str(c*n))
d2.pop('0', None)
if d1 == d2:
print c
break
c += 1
ZnJvbSBjb2xsZWN0aW9ucyBpbXBvcnQgQ291bnRlcgoKbSwgbiA9IDEsIDIKCmMgPSAxCgp3aGlsZSBUcnVlOgogICAgZDEgPSBDb3VudGVyKHN0cihjKm0pKQogICAgZDEucG9wKCcwJywgTm9uZSkKICAgIGQyID0gQ291bnRlcihzdHIoYypuKSkKICAgIGQyLnBvcCgnMCcsIE5vbmUpCgogICAgaWYgZDEgPT0gZDI6CiAgICAgICAgcHJpbnQgYwogICAgICAgIGJyZWFrCgogICAgYyArPSAx