#include <stdio.h>
int main(void) {
int n=0;
int sum=0;
while( n <= 100 )
{
if((n%3!=0)&&(n%5!=0)&&(n%10>=6)&&(n>=6))
sum =sum + n;
n = n + 1;
}
printf("3の倍数でもなく5の倍数でもない数字の合計は%dです。 \n",sum
); return 0;
}
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