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  1. #include<stdio.h>
  2. int f(int *a, int n){
  3. 	if(n<=0) return 0;
  4. 	else if (*a%2==0) return *a+f(a+1, n-1);
  5. 	else return *a-f(a+1, n-1);
  6.  
  7. }
  8. int main(){
  9. 	int a[]={12, 7, 13, 4, 11, 6};
  10. 	printf("\n%d\n", f(a,6));
  11. 	return 0;
  12. }
Success #stdin #stdout 0s 4300KB
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15
https://ideone.com/hCTJtd
language:
C++ (gcc 8.3)
created:
4 years ago
visibility:
public

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