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  1. #include <stdio.h>
  2.  
  3. int pow10[] = {1, 10, 100, 1000, 10000, 100000, 1000000, 10000000, 100000000, 1000000000};
  4.  
  5. int main(void) {
  6.     int num = 12345;
  7.     int n = 3;
  8.  
  9.     int log10 = 0;
  10.     while (pow10[log10] < num) {
  11.         log10++;
  12.     }
  13.     int divisor = pow10[log10-n];
  14.     int res = num / divisor;
  15.     printf("log10(num)+1=%d, divisor=%d, result=%d\n", log10, divisor, res);
  16.     return 0;
  17. }
Success #stdin #stdout 0s 1788KB
comments (?)
stdin 
Standard input is empty
stdout 
log10(num)+1=5, divisor=100, result=123
https://ideone.com/h90Itk
language:
C (gcc 8.3)
created:
12 years ago
visibility:
public

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