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  1. import re
  2. string = '[ 1234, jack, 1987-09-02]'
  3. pattern = re.compile(r"(\d+?),\s([a-zA-Z]+?),\s(\d{4}\-\d{2}\-\d{2})")
  4. print(pattern.search(string).groups())
  5.  
Success #stdin #stdout 0.03s 9936KB
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Standard input is empty
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('1234', 'jack', '1987-09-02')
https://ideone.com/gXdkQ2
language:
Python 3 (python  3.12)
created:
8 years ago
visibility:
public

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