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  1. #include <stdio.h>
  2. int x;
  3. int a() { return x++ + 1; }
  4. int b() { return x++ + 2; }
  5. int c() { return x++ + 3; }
  6.  
  7. int main() 
  8. {
  9.   int (* abc[])() = {&a, &b, &c};
  10.   int i = 0,
  11.       l = sizeof(abc)/sizeof(abc[0]);
  12.   for (; i < l; i++) { 
  13.     printf("Give me a %d for %d!\n", (*abc[i])(), i);
  14.   }
  15.   return 0;
  16. }
Success #stdin #stdout 0.01s 1676KB
comments (?)
stdin
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Standard input is empty
stdout
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Give me a 1 for 0!
Give me a 3 for 1!
Give me a 5 for 2!
https://ideone.com/fzt1SX
language:
C (gcc 8.3)
created:
11 years ago
visibility:
public

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