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  1. #include <stdio.h>
  2.  
  3. #define TABSIZE 3
  4.  
  5. double sum_tab(double tab[], size_t len);
  6. void print_tab(double tab[], size_t len);
  7.  
  8. int main(void) {
  9. 	double X = 100;
  10. 	double sr = X/TABSIZE;
  11. 	double tab_1[TABSIZE] = {0, 40, -1};
  12. 	double tab_2[TABSIZE];
  13.  
  14. 	double suma = sum_tab(tab_1, TABSIZE);
  15. 	//if(suma == 0.0) { suma = 1; }
  16.  
  17. 	for(size_t i=0;i<TABSIZE;++i) { tab_2[i] = tab_1[i]; }
  18. 	for(size_t i=0;i<TABSIZE;++i) {	tab_2[i] = tab_2[i] * sr; }
  19. 	double suma_tab_2 = sum_tab(tab_2, TABSIZE);
  20. 	double n = X/suma_tab_2;
  21. 	for(size_t i=0;i<TABSIZE;++i) {	tab_2[i] = tab_2[i] * n; }
  22.  
  23. 	puts("tab_1");
  24. 	print_tab(tab_1, TABSIZE);
  25. 	puts("\ntab_2");
  26. 	print_tab(tab_2, TABSIZE);
  27. 	puts("");
  28. 	printf("X = %5.5f\nsuma tablicy = %5.5f\n", X, sum_tab(tab_2, TABSIZE));
  29. 	return 0;
  30. }
  31.  
  32. double sum_tab(double tab[], size_t len) {
  33. 	double sum = 0;
  34. 	for(size_t i=0;i<len;++i) { sum += tab[i]; }
  35. 	return sum;
  36. }
  37.  
  38. void print_tab(double tab[], size_t len) {
  39. 	for(size_t i=0;i<len;++i) {
  40. 		printf("%5.5f ", tab[i]);
  41. 		if((i%5) == 4) { printf("\n"); }
  42. 	}
  43. }
Success #stdin #stdout 0s 2168KB
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stdin
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Standard input is empty
stdout
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tab_1
0.00000 40.00000 -1.00000 
tab_2
0.00000 102.56410 -2.56410 
X = 100.00000
suma tablicy = 100.00000
https://ideone.com/eouU4c
language:
C (gcc 8.3)
created:
7 years ago
visibility:
public

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