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  1. #define p(x) printf("%i",x);
  2. i,y,h;
  3. f(x){
  4.     for(i=y=x;(i-=h)>=0;){
  5.         p(y--)
  6.         h=floor(log10(y))+1;
  7.     }
  8.     if(i+=h)
  9.         p(h=floor(y/pow(10,i)))
  10.     p(x)
  11. }
  12.  
  13. n;main(){
  14. 	scanf("%i",&n);
  15. 	f(n);
  16. }
Success #stdin #stdout 0s 2160KB
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stdin
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99
stdout
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9998979695949392919089888786858483828180797877767574737271706968676665646362616059585756555453525150499
https://ideone.com/daQou1
language:
C (gcc 8.3)
created:
8 years ago
visibility:
public

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