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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int a=3,n=0;
  5. 	do
  6. 	{
  7. 		a=2*a-1;
  8. 		n=n+1;
  9.  
  10. 	}
  11. 	while(a<=10000);
  12. 	printf("%d回目で%dとなり、10000を超えます。\n",n,a);
  13. 	return 0;
  14. }
  15.  
Success #stdin #stdout 0s 5288KB
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Standard input is empty
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13回目で16385となり、10000を超えます。
https://ideone.com/dP00kA
language:
C (gcc 8.3)
created:
9 days ago
visibility:
public

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