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  1. #include <stdio.h>
  2. #include <string.h>
  3. #include <stdlib.h>
  4.  
  5. void split(char *ch,char **part1,char **part2,int *num){
  6.     int length=strlen(ch);
  7.     char *lc1,*lc2;
  8.     int i=0,j=0;
  9.     printf("value of length is %d\n",length);
  10.  
  11.     printf("this function recieved %s for splitting into pieces\n",ch);
  12.  
  13.     lc1=(char *)malloc(length*sizeof(char));
  14.     lc2=(char *)malloc(length*sizeof(char));
  15.  
  16.     while(ch[i]!=' '){
  17.         lc1[i]=ch[i];
  18.         printf("\nin loop with lc1[i] = %c and ch[i] =  %c",lc1[i],ch[i]);
  19.         i++;
  20.     }
  21.     lc1[i]='\0';
  22.     i++;
  23.     while(ch[i]!=' '){
  24.         lc2[j]=ch[i];
  25.         printf("\nin loop with lc2[j] = %c and ch[i] =  %c",lc2[j],ch[i]);
  26.         j++;
  27.         i++;
  28.     }
  29.     lc2[j]='\0';
  30.     i++;
  31.     *num=atoi(&ch[i]);
  32.  
  33.     *part1=lc1;
  34.     *part2=lc2;
  35.  
  36.     printf("\nsplit results are:\n");
  37.     printf("part1=%s and part2=%s and num=%d and lc1=%s lc2=%s    //this is surprising me\n",*part1,*part2,*num,lc1,lc2);
  38.  
  39. }
  40.  
  41. int main()
  42. {
  43.     int N,i,j,n,*numArray,count=0;
  44.     char **arr,*part1,*part2,*token;
  45.     scanf("%d",&N);
  46.     arr=malloc(N*sizeof *arr);
  47.     numArray=malloc(N*sizeof *numArray);
  48.     for(i=0;i<N;i++){
  49.         arr[i]=(char *)malloc(50*sizeof(char));
  50.     }
  51.  
  52.     for(i=0;i<N;i++){
  53.         printf("plz enter %d th :",i);
  54.         scanf(" ");
  55.         gets(&arr[i][0]);
  56.     }
  57.  
  58.     for(i=0;i<N;i++){
  59.         printf("%s\n",arr[i]);
  60.     }
  61.  
  62.     for(i=0;i<N;i++){
  63.         /*token=strtok(arr[i]," ");
  64.           part1=token;
  65.           token=strtok(NULL," ");
  66.           part2=token;
  67.           token=strtok(NULL," ");
  68.           n=atoi(token);*/
  69.         split(arr[i],&part1,&part2,&n);
  70.         //some logic to use part1 and part2 of the sentence
  71.     }
  72.     return 0;
  73.  
  74. }
  75.  
Success #stdin #stdout 0s 2296KB
comments (?)
stdin
copy 
1
abcd efgh 2
stdout
copy 
plz enter 0 th :abcd efgh 2
value of length is 11
this function recieved abcd efgh 2 for splitting into pieces

in loop with lc1[i] = a and ch[i] =  a
in loop with lc1[i] = b and ch[i] =  b
in loop with lc1[i] = c and ch[i] =  c
in loop with lc1[i] = d and ch[i] =  d
in loop with lc2[j] = e and ch[i] =  e
in loop with lc2[j] = f and ch[i] =  f
in loop with lc2[j] = g and ch[i] =  g
in loop with lc2[j] = h and ch[i] =  h
split results are:
part1=abcd and part2=efgh and num=2 and lc1=abcd lc2=efgh    //this is surprising me
https://ideone.com/cwcvrN
language:
C (gcc 8.3)
created:
8 years ago
visibility:
public

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