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  1. @(x,y)find((max(x))*min(y')==max(y')*min(x))
  2.  
  3. ans([1 2], [1 9; 2 5; 16 8])
Success #stdin #stdout 0.19s 64960KB
stdin
Standard input is empty
stdout
ans =

@(x, y) find ((max (x)) * min (y') == max (y') * min (x))

ans =  3