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  1. # http://c...content-available-to-author-only...e.com/q/78141/34718
  2.  
  3. x=input()
  4. i=1;k=0
  5. while i*i<x:k+=i*i;i+=2
  6. print k
  7.  
  8. f=lambda x:sum((n-~n)**2for n in range(x)if(n-~n)**2<x)
  9. #print f(10000)
Success #stdin #stdout 0.01s 9016KB
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stdin
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10000
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166650
https://ideone.com/bgLnNK
Sum the odd square numbers less than N
language:
Python (cpython 2.7.16)
created:
7 years ago
visibility:
secret

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