import struct
 
b26chars = "eocapgvqrynhmlsubixdftwzjk"
 
_ekeys = (69, 75, 89, 91)
_dkeys = (141, 99, 233, 211)
 
def _encrypt(n):
    packed = struct.pack(">L", n)
    encrypted = ''.join(chr((_ekeys[i] * ord(c)) % 256) for i, c in enumerate(packed))
    return struct.unpack(">L", encrypted)[0]
 
def _decrypt(n):
    packed = struct.pack(">L", n)
    decrypted = ''.join(chr((_dkeys[i] * ord(c)) % 256) for i, c in enumerate(packed))
    return struct.unpack(">L", decrypted)[0]
 
def b26(k):
    n = _encrypt(k)
    res = []
    while n > 0:
        n, m = divmod(n, 26)
        res.append(b26chars[m])
    if not res:
        return b26chars[0]
    res.reverse()
    return ''.join(res)
 
def unb26(s):
    n = 0
    for i, c in enumerate(s[::-1].lower()):
        n += b26chars.index(c)*26**i
    try:
        return _decrypt(n)
    except:
        return 0
 
def find(s, predicate, count = 1):
  n = unb26(s)
  i = 0
  while True:
    i = i + 1
    if (i & 65535) == 0:
      print 'i =', i
    id = b26(n + i)
    if predicate(id):
      print id, n + i, i
      count = count - 1
      if count == 0:
        break
 
def gets(s, count = 10):
  find(s, lambda x: (x[2] == x[3] and (x[3] == x[4] or x[1] == x[2])) or (x[0] == x[1] and x[1] == x[2]), count)
 
gets('igqsk', 30)
 
find('igqsk', lambda x: x.find('girl') != -1)

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