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  1. #include <stdio.h>
  2. #include <string.h>
  3.  
  4. int contem(char s1[], char s2[]) {
  5.     int j;
  6.     for (int i = 0; s2[i]; i++) {
  7.         for (j = 0; s1[j]; j++) {
  8.             if(s2[i] == s1[j]) {
  9.                 break;
  10.             }
  11.         }
  12.         if (s1[j] == '\0') {
  13.             return 0;
  14.         }
  15.     }
  16.     return 1;
  17. }
  18.  
  19. int main() {
  20.     char s[] = "abc";
  21.     char v[] = "cdeabf";
  22.      if(contem(v, s)) {
  23.         printf("'%s' contém todos os caracteres presentes em '%s'", v, s);
  24.     } else {
  25.         printf("'%s' não contém todos os caracteres presentes em '%s'", v, s);
  26.     }
  27.     return 0;
  28. }
Success #stdin #stdout 0s 2008KB
comments (?)
stdin
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Standard input is empty
stdout
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'cdeabf' contém todos os caracteres presentes em 'abc'
https://ideone.com/ZobDnV
language:
C99 (gcc 8.3)
created:
9 years ago
visibility:
public

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