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  1. #include <stdio.h>
  2.  
  3. double solve(const double a, const int n) {
  4.     double temp = a;
  5.     double result = 1.0 / a;
  6.     for (int i = 1; i <= n; i += 1) {
  7.         temp *= (a + i);
  8.         result += 1.0 / temp;
  9.     }
  10.     return result;
  11. }
  12.  
  13. int main() {
  14. 	int n;
  15.     double a;
  16.     scanf("%lf%i", &a, &n);
  17.     printf("%.4lf\n", solve(a, n));
  18. }
  19.  
Success #stdin #stdout 0s 2172KB
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3
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stdout
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https://ideone.com/YuHA7k
language:
C (gcc 8.3)
created:
8 years ago
visibility:
public

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